parser: remove unnecessary strlen()
André Goddard Rosa [Tue, 15 Dec 2009 02:01:08 +0000 (18:01 -0800)]
No functional change.  Cache strlen() result to avoid recalculating it up
to 3 times on the worst case.

Reduces code size a little by 32 bytes:
   text    data     bss     dec     hex filename
   1385       0       0    1385     569 lib/parser.o-BEFORE
   1353       0       0    1353     549 lib/parser.o-AFTER

Signed-off-by: André Goddard Rosa <andre.goddard@gmail.com>
Cc: Randy Dunlap <randy.dunlap@oracle.com>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>

lib/parser.c

index b00d020..fb34977 100644 (file)
@@ -56,13 +56,16 @@ static int match_one(char *s, const char *p, substring_t args[])
 
                args[argc].from = s;
                switch (*p++) {
-               case 's':
-                       if (strlen(s) == 0)
+               case 's': {
+                       size_t str_len = strlen(s);
+
+                       if (str_len == 0)
                                return 0;
-                       else if (len == -1 || len > strlen(s))
-                               len = strlen(s);
+                       if (len == -1 || len > str_len)
+                               len = str_len;
                        args[argc].to = s + len;
                        break;
+               }
                case 'd':
                        simple_strtol(s, &args[argc].to, 0);
                        goto num;