perf sched: Fix nsec to msec conversion
Frederic Weisbecker [Sat, 12 Sep 2009 23:59:05 +0000 (01:59 +0200)]
We are dividing a time in ns by 1e9. This is a nsec to sec
conversion. What we want is msecs. Fix it by dividing by 1e6.

Signed-off-by: Frederic Weisbecker <fweisbec@gmail.com>
Cc: Peter Zijlstra <a.p.zijlstra@chello.nl>
Cc: Mike Galbraith <efault@gmx.de>
Cc: Paul Mackerras <paulus@samba.org>
Cc: Arnaldo Carvalho de Melo <acme@redhat.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>

tools/perf/builtin-sched.c

index 4357027..67a0ba8 100644 (file)
@@ -1129,9 +1129,9 @@ static void output_lat_thread(struct task_atoms *atom_list)
        avg = atom_list->total_lat / atom_list->nb_atoms;
 
        printf("|%9.3f ms |%9llu | avg:%9.3f ms | max:%9.3f ms |\n",
-             (double)atom_list->total_runtime / 1e9,
-                atom_list->nb_atoms, (double)avg / 1e9,
-                (double)atom_list->max_lat / 1e9);
+             (double)atom_list->total_runtime / 1e6,
+                atom_list->nb_atoms, (double)avg / 1e6,
+                (double)atom_list->max_lat / 1e6);
 }
 
 static void __cmd_lat(void)
@@ -1157,7 +1157,7 @@ static void __cmd_lat(void)
 
        printf("-----------------------------------------------------------------------------------\n");
        printf(" TOTAL:            |%9.3f ms |%9Ld |\n",
-               (double)all_runtime/1e9, all_count);
+               (double)all_runtime/1e6, all_count);
        printf("---------------------------------------------\n");
 }